Charlotte’s LaMelo Ball Named N.B.A.’s Rookie of the Year

LaMelo Ball of the Charlotte Hornets won the N.B.A.’s Rookie of the Year Award on Wednesday, joining Larry Johnson and Emeka Okafor as players in the franchise’s history to receive the honor.
Ball, who before this season bypassed college ball to play professionally in Australia and had a stint in Lithuania while still in high school, received 84 of 99 first-place votes to beat out Minnesota’s Anthony Edwards despite Edwards’s second-half surge. Tyrese Haliburton of the Sacramento Kings finished third.
Selected with the No. 3 pick in the 2020 draft, Ball moved into Charlotte’s starting lineup in the 21st game of the season and, in tandem with the former All-Star Gordon Hayward and guard Terry Rozier, unexpectedly led the Hornets into contention for a top-six spot in the Eastern Conference. That push was derailed by a fractured right wrist Ball sustained on March 20 that forced him to miss 21 games, and Hayward was knocked out of the lineup on April 2 by a sprained right foot that sidelined him for the rest of the season.
Ball, who turns 20 in August, averaged 15.7 points, 5.9 rebounds and 6.1 assists per game. He also shot a respectable 43.6 percent from the field and 35.2 percent from 3-point range, after worrisome showings in both categories in the preseason (26.2 percent shooting overall and 27.3 percent on 3s in four games) amplified skepticism about his shooting ability as he made the transition to the N.B.A.


